Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} None of these Compilation clean but no output xyz Compilation fails abc None of these Compilation clean but no output xyz Compilation fails abc ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 1 (static x must be only accessed inside static methods) 49 Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 1 (static x must be only accessed inside static methods) 49 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }} one one 20 20 one two one two 20 one one 20 20 one two one two 20 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int...args){} void add(Integer... args){} static void add(int[]... args){} static void add(int args...){} static void add(int... args, int y){} static void add(int...args){} void add(Integer... args){} static void add(int[]... args){} static void add(int args...){} static void add(int... args, int y){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }} 0 Runtime Exception Compile with error None of these 5 0 Runtime Exception Compile with error None of these 5 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword At run-time At Compile-time Depends on the code None of these At run-time At Compile-time Depends on the code None of these ANSWER DOWNLOAD EXAMIANS APP
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