Declaration and Access Control
What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}}

5
6
0
Compile with error
Runtime Exception

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The program will lead to runtime error.
The program will lead to compilation error.
The will compile successfully and display 9 as output.
None of these
The program will compile successfully and display 10 as output.

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int...args){}
static void add(int args...){}
static void add(int... args, int y){}
void add(Integer... args){}
static void add(int[]... args){}

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