Declaration and Access Control
What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

BaseDerived
Compilation Error
Derived
Exception is thrown at runtime

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Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.
From within protected methods you do not have access to public methods.
This method is only accessible from inside the class itself and from inside all subclasses.
This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int...args){}
static void add(int[]... args){}
void add(Integer... args){}
static void add(int args...){}
static void add(int... args, int y){}

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Declaration and Access Control
A method within a class is only accessible by classes that are defined within the same package as the class of the method. Which one of the following is used to enforce such restriction?

Declare the method with the keyword protected.
Declare the method with the keyword public.
Declare the method with the keyword public and private.
Do not declare the method with any accessibility modifiers.
Declare the method with the keyword private.

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Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

IllegalArgumentException is thrown at runtime.
Hello2 InsideDemo 10
Compilation error.
InsideDemo 10 Hello2
InsideDemo 10 Hello2 hello1

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