Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. native final abstract volatile static native final abstract volatile static ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} None of these Compile time error. one two 0 one two 1 one two 10 None of these Compile time error. one two 0 one two 1 one two 10 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 4 (invalid argument type for method main) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 4 (invalid argument type for method main) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 3 (static methods can't make reference to non-static variables) 49 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }} A block static A None of these static A static block A A block static A None of these static A static block A ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. This method is only accessible from inside the class itself and from inside all subclasses. From within protected methods you do not have access to public methods. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. This method is only accessible from inside the class itself and from inside all subclasses. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}} Compile error at line 4 (invalid argument type for method main ) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't invoke this) Compile error at line 2 (constructors can't be static) 44 Compile error at line 4 (invalid argument type for method main ) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't invoke this) Compile error at line 2 (constructors can't be static) 44 ANSWER DOWNLOAD EXAMIANS APP
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