Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. native volatile final static abstract native volatile final static abstract ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} xyz Compilation clean but no output abc None of these Compilation fails xyz Compilation clean but no output abc None of these Compilation fails ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program has a compilation error because we cannot assign radius to radius. The program does not compile because Circle does not have a default constructor. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program has a compilation error because we cannot assign radius to radius. The program does not compile because Circle does not have a default constructor. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }} Derived Compilation Error Exception is thrown at runtime BaseDerived Derived Compilation Error Exception is thrown at runtime BaseDerived ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }} Runtime Exception Compile with error None of these 0 5 Runtime Exception Compile with error None of these 0 5 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} Hello2 InsideDemo 10 InsideDemo 10 Hello2 Compilation error. InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 InsideDemo 10 Hello2 Compilation error. InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. ANSWER DOWNLOAD EXAMIANS APP
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