Declaration and Access Control Name the keyword that makes a variable belong to a class, rather than being defined for each instance of the class. final volatile native static abstract final volatile native static abstract ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword At Compile-time Depends on the code None of these At run-time At Compile-time Depends on the code None of these At run-time ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) Compile error at line 3 (static methods can't make reference to non-static variables) 49 Compile error at line 1 (static x must be only accessed inside static methods) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} Compilation clean but no output Compilation fails abc None of these xyz Compilation clean but no output Compilation fails abc None of these xyz ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The program will compile successfully and display 10 as output. The will compile successfully and display 9 as output. The program will lead to runtime error. The program will lead to compilation error. None of these The program will compile successfully and display 10 as output. The will compile successfully and display 9 as output. The program will lead to runtime error. The program will lead to compilation error. None of these ANSWER DOWNLOAD EXAMIANS APP
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