Declaration and Access Control
Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }}

one two
one 20
20
one
one two 20

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Declaration and Access Control
What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}}

Compile error at line 4 (invalid argument type for method main )
Compile error at line 1 (static x must be only accessed inside static methods)
Compile error at line 2 (constructors can't be static)
44
Compile error at line 3 (static methods can't invoke this)

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Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.
From within protected methods you do not have access to public methods.
This method is only accessible from inside the class itself and from inside all subclasses.
This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

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Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

InsideDemo 10 Hello2
Compilation error.
Hello2 InsideDemo 10
InsideDemo 10 Hello2 hello1
IllegalArgumentException is thrown at runtime.

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