Declaration and Access Control Choose the correct statement. Restriction on static methods are: I. They can only call other static methods.II. They must only access static data.III. They cannot refer this or super in any way. Only (III) (II) and (III) (I), (II) and (III) Only (I) (I) and (II) Only (III) (II) and (III) (I), (II) and (III) Only (I) (I) and (II) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct? This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. This method is accessible from within the class itself and from within all classes defined in the same package as the class itself. From within protected methods you do not have access to public methods. This method is only accessible from inside the class itself and from inside all subclasses. In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} void add(Integer... args){} static void add(int[]... args){} static void add(int args...){} static void add(int...args){} static void add(int... args, int y){} void add(Integer... args){} static void add(int[]... args){} static void add(int args...){} static void add(int...args){} static void add(int... args, int y){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }} Exception is thrown at runtime Compilation Error Derived BaseDerived Exception is thrown at runtime Compilation Error Derived BaseDerived ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }} 20 one two 20 one two one one 20 20 one two 20 one two one one 20 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} InsideDemo 10 Hello2 IllegalArgumentException is thrown at runtime. InsideDemo 10 Hello2 hello1 Compilation error. Hello2 InsideDemo 10 InsideDemo 10 Hello2 IllegalArgumentException is thrown at runtime. InsideDemo 10 Hello2 hello1 Compilation error. Hello2 InsideDemo 10 ANSWER DOWNLOAD EXAMIANS APP
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