Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A();

Declaration and Access Control
Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A();

1 and 3

3 and 4

2 and 4

1 and 2

1 and 3

3 and 4

2 and 4

1 and 2

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Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

From within protected methods you do not have access to public methods.

This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

This method is only accessible from inside the class itself and from inside all subclasses.

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

From within protected methods you do not have access to public methods.

This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

This method is only accessible from inside the class itself and from inside all subclasses.

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

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Declaration and Access Control
What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Exception is thrown at runtime

BaseDerived

Derived

Compilation Error

Exception is thrown at runtime

BaseDerived

Derived

Compilation Error

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Declaration and Access Control
You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Compiles and runs with no output.

It will fail to compile.

Runtime error

Compiles and runs printing

Compiles and runs with no output.

It will fail to compile.

Runtime error

Compiles and runs printing

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Declaration and Access Control
What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

one two 0

None of these

one two 1

one two 10

Compile time error.

one two 0

None of these

one two 1

one two 10

Compile time error.

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The program will compile successfully and display 10 as output.

The program will lead to runtime error.

The program will lead to compilation error.

None of these

The will compile successfully and display 9 as output.

The program will compile successfully and display 10 as output.

The program will lead to runtime error.

The program will lead to compilation error.

None of these

The will compile successfully and display 9 as output.

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Declaration and Access Control

Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

Declaration and Access Control What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

Declaration and Access Control
What is the result of compiling and running the following code?class Base{ private Base(){ System.out.print("Base"); }}public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); }}

Declaration and Access Control
You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this?

Declaration and Access Control
What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}