Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }}

Declaration and Access Control
Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }}

The program has a compilation error because it does not have a main method.

The program has a compilation error because we cannot assign radius to radius.

The program does not compile because Circle does not have a default constructor.

The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0.

The program has a compilation error because it does not have a main method.

The program has a compilation error because we cannot assign radius to radius.

The program does not compile because Circle does not have a default constructor.

The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0.

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Declaration and Access Control
What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

Compile time error.

one two 0

one two 1

one two 10

None of these

Compile time error.

one two 0

one two 1

one two 10

None of these

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Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

This method is only accessible from inside the class itself and from inside all subclasses.

From within protected methods you do not have access to public methods.

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

This method is only accessible from inside the class itself and from inside all subclasses.

From within protected methods you do not have access to public methods.

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

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Declaration and Access Control
Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A();

1 and 2

2 and 4

1 and 3

3 and 4

1 and 2

2 and 4

1 and 3

3 and 4

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Declaration and Access Control
What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }}

None of these

static block A

A block static

A

static A

None of these

static block A

A block static

A

static A

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Declaration and Access Control
What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.

one

two

None of these

Compile error - char can't be permitted in switch statement.

Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.

one

two

None of these

Compile error - char can't be permitted in switch statement.

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Declaration and Access Control

Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }}

Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

Declaration and Access Control Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

Declaration and Access Control What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }}

Declaration and Access Control What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

Declaration and Access Control
Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }}

Declaration and Access Control
What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }}

Declaration and Access Control
Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

Declaration and Access Control
What is the output for the below code ?public class A{ static{ System.out.println("static"); } { System.out.println("block"); } public A(){ System.out.println("A"); } public static void main(String[] args){ A a = new A(); }}

Declaration and Access Control
What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}