Declaration and Access Control The object is created with new keyword Depends on the code At Compile-time None of these At run-time Depends on the code At Compile-time None of these At run-time ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} None of these Compile time error. one two 10 one two 0 one two 1 None of these Compile time error. one two 10 one two 0 one two 1 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}} 44 Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't invoke this) Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) 44 Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 3 (static methods can't invoke this) Compile error at line 4 (invalid argument type for method main ) Compile error at line 2 (constructors can't be static) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }} The program will lead to runtime error. The program will lead to compilation error. The will compile successfully and display 9 as output. The program will compile successfully and display 10 as output. None of these The program will lead to runtime error. The program will lead to compilation error. The will compile successfully and display 9 as output. The program will compile successfully and display 10 as output. None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? Compiles and runs printing Compiles and runs with no output. It will fail to compile. Runtime error Compiles and runs printing Compiles and runs with no output. It will fail to compile. Runtime error ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} Compilation error. IllegalArgumentException is thrown at runtime. InsideDemo 10 Hello2 InsideDemo 10 Hello2 hello1 Hello2 InsideDemo 10 Compilation error. IllegalArgumentException is thrown at runtime. InsideDemo 10 Hello2 InsideDemo 10 Hello2 hello1 Hello2 InsideDemo 10 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS