Declaration and Access Control The object is created with new keyword At run-time Depends on the code None of these At Compile-time At run-time Depends on the code None of these At Compile-time ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }} None of these 0 Runtime Exception 5 Compile with error None of these 0 Runtime Exception 5 Compile with error ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:class A{{System.out.print("b1 ");}public A(){System.out.print("b2 ");}}class B extends A{static{System.out.print("r1 ");}public B(){System.out.print("r2 ");}{System.out.print("r3 ");}static{System.out.print("r4 ");}}public class Test extends B{public static void main(String[] args){System.out.print("pre ");new Test();System.out.println("post ");}} r1 r4 pre b1 b2 post r3 r2 r1 r4 pre b1 b2 post pre r1 r4 b1 b2 r2 r3 post Compilation fail r1 r4 pre b1 b2 r3 r2 post r1 r4 pre b1 b2 post r3 r2 r1 r4 pre b1 b2 post pre r1 r4 b1 b2 r2 r3 post Compilation fail r1 r4 pre b1 b2 r3 r2 post ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program does not compile because Circle does not have a default constructor. The program has a compilation error because we cannot assign radius to radius. The program has a compilation error because it does not have a main method. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program does not compile because Circle does not have a default constructor. The program has a compilation error because we cannot assign radius to radius. The program has a compilation error because it does not have a main method. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int[]... args){} void add(Integer... args){} static void add(int... args, int y){} static void add(int args...){} static void add(int...args){} static void add(int[]... args){} void add(Integer... args){} static void add(int... args, int y){} static void add(int args...){} static void add(int...args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} xyz Compilation fails None of these abc Compilation clean but no output xyz Compilation fails None of these abc Compilation clean but no output ANSWER DOWNLOAD EXAMIANS APP
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