Declaration and Access Control The object is created with new keyword At Compile-time At run-time None of these Depends on the code At Compile-time At run-time None of these Depends on the code ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A(); 1 and 2 3 and 4 1 and 3 2 and 4 1 and 2 3 and 4 1 and 3 2 and 4 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 0 Runtime Exception 6 Compile with error 5 0 Runtime Exception 6 Compile with error 5 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here} static void add(int... args, int y){} static void add(int[]... args){} static void add(int args...){} void add(Integer... args){} static void add(int...args){} static void add(int... args, int y){} static void add(int[]... args){} static void add(int args...){} void add(Integer... args){} static void add(int...args){} ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} None of these abc xyz Compilation clean but no output Compilation fails None of these abc xyz Compilation clean but no output Compilation fails ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }} one two 20 20 one one 20 one two one two 20 20 one one 20 one two ANSWER DOWNLOAD EXAMIANS APP
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