Declaration and Access Control The object is created with new keyword At Compile-time None of these Depends on the code At run-time At Compile-time None of these Depends on the code At run-time ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} InsideDemo 10 Hello2 hello1 InsideDemo 10 Hello2 Compilation error. Hello2 InsideDemo 10 IllegalArgumentException is thrown at runtime. InsideDemo 10 Hello2 hello1 InsideDemo 10 Hello2 Compilation error. Hello2 InsideDemo 10 IllegalArgumentException is thrown at runtime. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} Compile with error 0 5 Runtime Exception 6 Compile with error 0 5 Runtime Exception 6 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }} The program has a compilation error because we cannot assign radius to radius. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program does not compile because Circle does not have a default constructor. The program has a compilation error because we cannot assign radius to radius. The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0. The program has a compilation error because it does not have a main method. The program does not compile because Circle does not have a default constructor. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control You have the following code in a file called Test.javaclass Base{ public static void main(String[] args){ System.out.println("Hello"); }}public class Test extends Base{}What will happen if you try to compile and run this? Compiles and runs with no output. Runtime error It will fail to compile. Compiles and runs printing Compiles and runs with no output. Runtime error It will fail to compile. Compiles and runs printing ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }} Compile with error 0 None of these 5 Runtime Exception Compile with error 0 None of these 5 Runtime Exception ANSWER DOWNLOAD EXAMIANS APP
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