Declaration and Access Control What can directly access and change the value of the variable qusNo?package com.mypackage;public class Test{ private int qusNo = 100;} Only the Test class. None of these Any class in com.mypackage package. Any class. Any class that extends Test. Only the Test class. None of these Any class in com.mypackage package. Any class. Any class that extends Test. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control A package is a collection of Editing tools and Interfaces Classes Editing tools Classes and Interfaces Interfaces Editing tools and Interfaces Classes Editing tools Classes and Interfaces Interfaces ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A(); 2 and 4 1 and 2 1 and 3 3 and 4 2 and 4 1 and 2 1 and 3 3 and 4 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{ public static void main(String[] args){ String value = "abc"; changeValue(value); System.out.println(value); } public static void changeValue(String a){ a = "xyz"; }} Compilation clean but no output Compilation fails abc xyz None of these Compilation clean but no output Compilation fails abc xyz None of these ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What is the result of compiling and running the following code?public class Tester{static int x = 4;int y = 9; public Tester(){System.out.print(this.x); // line 1printVariables();}public static void printVariables(){System.out.print(x); // line 2System.out.print(y); // line 3}public static void main(String... args) { // line 4new Tester();}} Compile error at line 2 (must access x by writing Tester.x) 49 Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 4 (invalid argument type for method main) Compile error at line 2 (must access x by writing Tester.x) 49 Compile error at line 3 (static methods can't make reference to non-static variables) Compile error at line 1 (static x must be only accessed inside static methods) Compile error at line 4 (invalid argument type for method main) ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output after compiling and running following program code?public class Test{ static int a; public static void main(String[] args){ System.out.println("one"); call(1); } static void call(int a){ this.a=10; System.out.println("two "+a); }} one two 1 Compile time error. one two 0 None of these one two 10 one two 1 Compile time error. one two 0 None of these one two 10 ANSWER DOWNLOAD EXAMIANS APP
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