Declaration and Access Control What can directly access and change the value of the variable qusNo?package com.mypackage;public class Test{ private int qusNo = 100;} Any class. None of these Any class that extends Test. Only the Test class. Any class in com.mypackage package. Any class. None of these Any class that extends Test. Only the Test class. Any class in com.mypackage package. ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control A package is a collection of Classes and Interfaces Classes Interfaces Editing tools Editing tools and Interfaces Classes and Interfaces Classes Interfaces Editing tools Editing tools and Interfaces ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control What will be the output?public class Test{static{int a = 5;}public static void main(String args[]){new Test().call();}void call(){this.a++;System.out.print(this.a);}} 6 Compile with error Runtime Exception 5 0 6 Compile with error Runtime Exception 5 0 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A(); 3 and 4 1 and 2 1 and 3 2 and 4 3 and 4 1 and 2 1 and 3 2 and 4 ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control The object is created with new keyword None of these At run-time At Compile-time Depends on the code None of these At run-time At Compile-time Depends on the code ANSWER DOWNLOAD EXAMIANS APP
Declaration and Access Control Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}} InsideDemo 10 Hello2 Compilation error. InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 InsideDemo 10 Hello2 Compilation error. InsideDemo 10 Hello2 hello1 IllegalArgumentException is thrown at runtime. Hello2 InsideDemo 10 ANSWER DOWNLOAD EXAMIANS APP
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