Declaration and Access Control
What can directly access and change the value of the variable qusNo?package com.mypackage;public class Test{ private int qusNo = 100;}

Any class in com.mypackage package.
None of these
Any class.
Any class that extends Test.
Only the Test class.

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Declaration and Access Control
Consider the following two classes declared and defined in two different packages, what can be added in class B to form what considered a correct access to class A from main() method of class B?package subPackage;public class A { }package anotherPackage;// line 1public class B{public static void main(String[] args){// line 2}}1. At line1 add noting; At line2 add: new A();2. At line 1 add: import package.*; at line 2 add : new subPackage.A();3. At line 1 add: import subPackage.*; at line 2 add : new A();4. At line 1 add: import subPackage.A; at line 2 add : new A();

1 and 3
1 and 2
2 and 4
3 and 4

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Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int...args){}
static void add(int[]... args){}
void add(Integer... args){}
static void add(int args...){}
static void add(int... args, int y){}

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Declaration and Access Control
What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

None of these
The program will lead to runtime error.
The will compile successfully and display 9 as output.
The program will lead to compilation error.
The program will compile successfully and display 10 as output.

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