Theory of Structures The equivalent length is of a column of length having both the ends fixed, is 2 L L l L/2 2 L L l L/2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A cantilever of length 2 cm and depth 10 cm tapers in plan from a width 24 cm to zero at its free end. If the modulus of elasticity of the material is 0.2 × 106 N/mm², the deflection of the free end, is 4 mm 5 mm 3 mm 2 mm 4 mm 5 mm 3 mm 2 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures At any point of a beam, the section modulus may be obtained by dividing the moment of inertia of the section by Maximum tensile stress at the section Maximum compressive stress at the section Depth of the neutral axis Depth of the section Maximum tensile stress at the section Maximum compressive stress at the section Depth of the neutral axis Depth of the section ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A cantilever of length ‘L’ is subjected to a bending moment ‘M’ at its free end. If EI is the flexural rigidity of the section, the deflection of the free end, is ML/EI ML/2EI ML²/3EI ML²/2EI ML/EI ML/2EI ML²/3EI ML²/2EI ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Perry Parabolic formula Straight line formula Rankine Perry Parabolic formula Straight line formula Rankine ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of shear stress and shear strain of an elastic material, is Shear Modulus Both A. and B. Modulus of Rigidity Modulus of Elasticity Shear Modulus Both A. and B. Modulus of Rigidity Modulus of Elasticity ANSWER DOWNLOAD EXAMIANS APP
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