Theory of Structures The general expression for the B.M. of a beam of length l is the beam carries M = (wl/2) x – (wx²/2) An isolated load at mid span A load varying linearly from zero at one end to w at the other end None of these A uniformly distributed load w/unit length An isolated load at mid span A load varying linearly from zero at one end to w at the other end None of these A uniformly distributed load w/unit length ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) E = 2N (1 + 1/m) All of these (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) E = 2N (1 + 1/m) All of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For the close coil helical spring of the maximum deflection is 8WD3n/d4N 2WD3n/d4N WD3n/d4N 4W²D3n/d4N 8WD3n/d4N 2WD3n/d4N WD3n/d4N 4W²D3n/d4N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the maximum deflections of a simply supported beam with a central load W and of a cantilever of same length and with a load W at its free end, is 1/10 1/8 1/16 1/12 1/10 1/8 1/16 1/12 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum bending moment for a simply supported beam with a uniformly distributed load w/unit length, is WI²/4 WI²/12 WI²/8 WI/2 WI²/4 WI²/12 WI²/8 WI/2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Principal planes are subjected to Normal stresses only Normal stresses as well as tangential stresses Tangential stresses only None of these Normal stresses only Normal stresses as well as tangential stresses Tangential stresses only None of these ANSWER DOWNLOAD EXAMIANS APP
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