Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Straight line formula Perry Parabolic formula Rankine Straight line formula Perry Parabolic formula Rankine ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A shaft subjected to a bending moment M and a torque T, experiences Maximum shear stress = 16 T/πd³ Both A and B Maximum bending stress = 32M/πd³ Neither A nor B Maximum shear stress = 16 T/πd³ Both A and B Maximum bending stress = 32M/πd³ Neither A nor B ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel bar 5 m × 50 mm is loaded with 250,000 N. If the modulus of elasticity of the material is 0.2 MN/mm² and Poisson’s ratio is 0.25, the change in the volume of the bar is: 2.125 cm³ 1.125 cm³ 4.125 cm² 3.125 cm³ 2.125 cm³ 1.125 cm³ 4.125 cm² 3.125 cm³ ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A rolled steel joist is simply supported at its ends and carries a uniformly distributed load which causes a maximum deflection of 10 mm and slope at the ends of 0.002 radian. The length of the joist will be, 15 M 13 M 16 m 14 M 15 M 13 M 16 m 14 M ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Slenderness ratio of a long column, is Radius of gyration divided by area of cross-section Area of cross-section divided by least radius of gyration Area of cross-section divided by radius of gyration Length of column divided by least radius of gyration Radius of gyration divided by area of cross-section Area of cross-section divided by least radius of gyration Area of cross-section divided by radius of gyration Length of column divided by least radius of gyration ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Stress may be expressed in Newtons Per centimetre square (N/cm²) Per metre square (N/m2) Per millimetre square (N/mm²) None of these Per centimetre square (N/cm²) Per metre square (N/m2) Per millimetre square (N/mm²) None of these ANSWER DOWNLOAD EXAMIANS APP
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