Theory of Structures If a concrete column 200 × 200 mm in cross-section is reinforced with four steel bars of 1200 mm² total cross-sectional area. Calculate the safe load for the column if permissible stress in concrete is 5 N/mm² and Es is 15 Ec 294 MN 264 MN 274 MN 284 MN 294 MN 264 MN 274 MN 284 MN ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported rolled steel joist 8 m long carries a uniformly distributed load over it span so that the maximum bending stress is 75 N/mm². If the slope at the ends is 0.005 radian and the value of E = 0.2 × 106 N/mm², the depth of the joist, is 300 mm 250 mm 400 mm 200 mm 300 mm 250 mm 400 mm 200 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The moment of inertia of a triangular section (height h, base b) about its base, is bh³/12 b³h/12 b²h/12 bh²/12 bh³/12 b³h/12 b²h/12 bh²/12 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The locus of the moment of inertia about inclined axes to the principal axis, is Ellipse Circle Straight line Parabola Ellipse Circle Straight line Parabola ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A rolled steel joist is simply supported at its ends and carries a uniformly distributed load which causes a maximum deflection of 10 mm and slope at the ends of 0.002 radian. The length of the joist will be, 15 M 14 M 16 m 13 M 15 M 14 M 16 m 13 M ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Slenderness ratio of a long column, is Length of column divided by least radius of gyration Area of cross-section divided by least radius of gyration Area of cross-section divided by radius of gyration Radius of gyration divided by area of cross-section Length of column divided by least radius of gyration Area of cross-section divided by least radius of gyration Area of cross-section divided by radius of gyration Radius of gyration divided by area of cross-section ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS