Theory of Structures The point of contraflexure is the point where M. is maximum S.F. is zero M. changes sign M. is minimum M. is maximum S.F. is zero M. changes sign M. is minimum ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures parabolic arch of span and rise , is given by The equation of a y = 2h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) y = 3h/l² × (1 – x) y = 2h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) y = 3h/l² × (1 – x) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of crippling loads of a column having both the ends fixed to the column having both the ends hinged, is 3 1 4 2 3 1 4 2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum deflection due to a load W at the free end of a cantilever of length L and having flexural rigidity EI, is WL²/3EI WL3/3EI WL3/2EI WL²/2EI WL²/3EI WL3/3EI WL3/2EI WL²/2EI ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum magnitude of shear stress due to shear force F on a rectangular section of area A at the neutral axis, is 2F/3A F/2A 3F/2A F/A 2F/3A F/2A 3F/2A F/A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good E = 3K (1 – 2/m) All of these E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) All of these E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP
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