RCC Structures Design Design of a two way slab simply supported on edges and having no provision to prevent the corners from lifting, is made by Rankine Grashoff formula Grashoff formula Rankine formula Marcus formula Rankine Grashoff formula Grashoff formula Rankine formula Marcus formula ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The toe projection of foundation slabs is taken As one third of the base Below ground surface As one sixth of overall height of the wall Equal to heel slab As one third of the base Below ground surface As one sixth of overall height of the wall Equal to heel slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In the zone of R.C.C. beam where shear stress is less than 5 kg/cm², nominal reinforcement is provided at a pitch of Lever arm of the section One-third lever arm of the section One and half lever arm of the section One-half lever arm of the section Lever arm of the section One-third lever arm of the section One and half lever arm of the section One-half lever arm of the section ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Total pressure on the vertical face of a retaining wall of height h acts parallel to free surface and from the base at a distance of h/3 h/2 h/4 2h/3 h/3 h/2 h/4 2h/3 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member is preferred because All listed here Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress Removal of cracks in the members due to shrinkage All listed here Large size of long beams carrying large shear force need not be adopted Its dimensions are not decided from the diagonal tensile stress Removal of cracks in the members due to shrinkage ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² ANSWER DOWNLOAD EXAMIANS APP
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