Problems on H.C.F and L.C.M Which of the following fractions is the largest? 63/80 31/40 7/8 13/16 63/80 31/40 7/8 13/16 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively 131 133 127 129 131 133 127 129 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127
Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 548 389 443 216 548 389 443 216 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M LCM of 18 and 27 is: 85 91 89 54 85 91 89 54 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 23/37 31/45 11/13 17/29 23/37 31/45 11/13 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M Three friends Raju , Ramesh and Sunil start running around a circular stadium and complete a single round in 24 s, 36 s and 40 s, respectively. After how many minutes will they meet against at the sta 6 minutes 5 minutes 8 minutes 7 minutes 6 minutes 5 minutes 8 minutes 7 minutes ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 24 = 3 × 2 × 2 × 2 = 3 × 2³ 36 = 3 × 3 × 2 × 2 = 3² × 2²and 40 = 2 × 2 × 2 × 5 = 5¹ × 23 LCM of 24, 36 and 40 = 3² × 2³ × 5 = 9 × 8 × 5 = 360Hence, they will meet again at the starting point after 360 s, i.e., 6 min
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