Problems on H.C.F and L.C.M The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag 5 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 8 : 27 : 12 hrs. 5 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 8 : 27 : 12 hrs. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively 127 131 129 133 127 131 129 133 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In this type of question, its obvious we need to calculate the HCF, trick isHCF of (1661 - 10) and (2045 -13)= HCF (1651, 2032) = 127
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12,15 and 18 is : 10015 10010 10080 10020 10015 10010 10080 10020 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP NA
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 17/29 11/13 23/37 31/45 17/29 11/13 23/37 31/45 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M The H.C.F. of 1.75, 5.6 and 7 is: 0.7 0.07 3.5 0.35 0.7 0.07 3.5 0.35 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 3 minute 48 seconds 2 minute 48 seconds 4 minute 48 seconds 1 minute 48 seconds 3 minute 48 seconds 2 minute 48 seconds 4 minute 48 seconds 1 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
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