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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the HCF of 2.1, 1.05 and 0.63

3.21
0.21
2.21
1.21

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

To solve this question quickly, first remove decimal by multiplying each term with 100,Then terms become 210, 105, 63Then HCF of above terms is 21, So Answer is 0.21

Problems on H.C.F and L.C.M
The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is

90
10
70
46

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case?

19
18
16
17

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

31/45
23/37
11/13
17/29

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
The least number of four digits which is divisible by 15, 25, 40 and 75 is:

9000
9400
9600
9800

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder .

4683
3683
2683
1683

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 5,6,7,8 = 840.    Required number is of the form 840k + 3     Least value of k for which (840k + 3) is divisible by 9 is k = 2. Required number = (840 X 2 + 3)=1683

MORE MCQ ON Problems on H.C.F and L.C.M

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