JAVA Exceptions
Given the following piece of code:class SalaryCalculationException extends Exception{}class Person{ public void calculateSalary() throws SalaryCalculationException{ //... throw new SalaryCalculationException(); //... }}class Company{ public void paySalaries(){ new Person().calculateSalary(); }}Which of the following statements is correct?1. This code will compile without any problems.2. This code will compile if in method paySalaries() we return a boolean in stead of void.3. This code will compile if we add a try-catch block in paySalaries().4. This code will compile if we add throws SalaryCalculationException in the signature of method paySalaries().

1 and 2
2 and 3
3 and 4
1 and 4
2 and 4

ANSWER DOWNLOAD EXAMIANS APP

JAVA Exceptions
What is the output for the below code ?import java.io.FileNotFoundException;class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); }}class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); }}public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); }}

printName()
Compilation fails-Exception NullPointerException is not compatible with throws clause in
Name-B
Compilation succeed but no output
Value-A
None of these

ANSWER DOWNLOAD EXAMIANS APP

JAVA Exceptions
What will be the result after the class Test execution?class A{ public void doA(){ B b = new B(); b.dobB(); System.out.print("doA"); }}class B{ public void dobB(){ C c = new C(); c.doC(); System.out.print("doB"); }}class C{ public void doC(){ if(true) throw new NullPointerException(); System.out.print("doC"); }}public class Test{ public static void main(String args[]){ try{ A a = new A(); a.doA(); }catch(Exception ex){ System.out.print("error"); } }}

"doAdoBdoC" is printed
"error" is printed
"doBdoAerror" is printed
nothing is printed
"doCdoBdoA" is printed

ANSWER DOWNLOAD EXAMIANS APP

JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

"null pointer exception" is printed.
Compilation fails saying NullPointerException has already been caught.
"one" is printed.
None of these
"exception" is printed.

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON JAVA Exceptions