JAVA Exceptions
What will be the output?class MyClass{ public String test(){ try{ System.out.print("One"); return ""; } finally{ System.out.print("Two"); } }}public class Test{ public static void main(String args[]){ MyClass m = new MyClass(); m.test(); }}

One
Compilation Error
Two
One Two
None of these

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JAVA Exceptions
What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }}

There is a NullPointerException. There is an Exception.
There is a NullPointerException.
This code will not compile, because in Java there are no pointers.
There is a NullPointerException. Everything went fine.

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

"one" is printed.
"null pointer exception" is printed.
Compilation fails saying NullPointerException has already been caught.
None of these
"exception" is printed.

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