JAVA Exceptions
What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }}

There is a NullPointerException. Everything went fine.
This code will not compile, because in Java there are no pointers.
There is a NullPointerException. There is an Exception.
There is a NullPointerException.

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

Compilation fails saying NullPointerException has already been caught.
None of these
"exception" is printed.
"one" is printed.
"null pointer exception" is printed.

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JAVA Exceptions
What will be the result after the class Test execution?class A{ public void doA(){ B b = new B(); b.dobB(); System.out.print("doA"); }}class B{ public void dobB(){ C c = new C(); c.doC(); System.out.print("doB"); }}class C{ public void doC(){ if(true) throw new NullPointerException(); System.out.print("doC"); }}public class Test{ public static void main(String args[]){ try{ A a = new A(); a.doA(); }catch(Exception ex){ System.out.print("error"); } }}

"doBdoAerror" is printed
nothing is printed
"error" is printed
"doCdoBdoA" is printed
"doAdoBdoC" is printed

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