JAVA Exceptions
What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }}

This code will not compile, because in Java there are no pointers.
There is a NullPointerException. Everything went fine.
There is a NullPointerException.
There is a NullPointerException. There is an Exception.

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JAVA Exceptions
Given the following piece of code:class SalaryCalculationException extends Exception{}class Person{ public void calculateSalary() throws SalaryCalculationException{ //... throw new SalaryCalculationException(); //... }}class Company{ public void paySalaries(){ new Person().calculateSalary(); }}Which of the following statements is correct?1. This code will compile without any problems.2. This code will compile if in method paySalaries() we return a boolean in stead of void.3. This code will compile if we add a try-catch block in paySalaries().4. This code will compile if we add throws SalaryCalculationException in the signature of method paySalaries().

3 and 4
1 and 4
2 and 4
1 and 2
2 and 3

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