JAVA Exceptions Which exception is thrown when divide by zero statement executes? NullPointerException NumberFormatException ArithmeticException None of these NullPointerException NumberFormatException ArithmeticException None of these ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions Which of the following blocks execute compulsorily whether exception is caught or not. throws finally throw catch throws finally throw catch ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What is the output of the following program code?public class Test{ public static void main(String args[]){ try{ int i; return; } catch(Exception e){ System.out.print("inCatchBlock"); } finally{ System.out.println("inFinallyBlock"); } }} inFinallyBlock The program will return without printing anything inCatchBlock inCatchBlock inFinallyBlock inFinallyBlock The program will return without printing anything inCatchBlock inCatchBlock inFinallyBlock ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions Determine output of the following program code?public class Test{ public static void main(String args[]){ int i; try{ i = calculate(); System.out.println(i); }catch(Exception e){ System.out.println("Error occured"); } } static int calculate(){ return (7/2); }} Compilation Error 3.5 Error occured 3 None of these Compilation Error 3.5 Error occured 3 None of these ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }} Prints out: Finally Compile with error Prints out: Exception Finally Prints out: Exception None of these Prints out: Finally Compile with error Prints out: Exception Finally Prints out: Exception None of these ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }} None of these Compilation fails saying NullPointerException has already been caught. "null pointer exception" is printed. "one" is printed. "exception" is printed. None of these Compilation fails saying NullPointerException has already been caught. "null pointer exception" is printed. "one" is printed. "exception" is printed. ANSWER DOWNLOAD EXAMIANS APP
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