JAVA Exceptions Which exception is thrown when divide by zero statement executes? ArithmeticException NumberFormatException None of these NullPointerException ArithmeticException NumberFormatException None of these NullPointerException ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }} "null pointer exception" is printed. "exception" is printed. None of these Compilation fails saying NullPointerException has already been caught. "one" is printed. "null pointer exception" is printed. "exception" is printed. None of these Compilation fails saying NullPointerException has already been caught. "one" is printed. ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What will be the result after the class Test execution?class A{ public void doA(){ B b = new B(); b.dobB(); System.out.print("doA"); }}class B{ public void dobB(){ C c = new C(); c.doC(); System.out.print("doB"); }}class C{ public void doC(){ if(true) throw new NullPointerException(); System.out.print("doC"); }}public class Test{ public static void main(String args[]){ try{ A a = new A(); a.doA(); }catch(Exception ex){ System.out.print("error"); } }} "doCdoBdoA" is printed "error" is printed nothing is printed "doAdoBdoC" is printed "doBdoAerror" is printed "doCdoBdoA" is printed "error" is printed nothing is printed "doAdoBdoC" is printed "doBdoAerror" is printed ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions Exception generated in try block is caught in ........... block. finally throw throws catch finally throw throws catch ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What is the output for the below code ?import java.io.FileNotFoundException;class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); }}class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); }}public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); }} Name-B None of these Value-A Compilation succeed but no output Compilation fails-Exception NullPointerException is not compatible with throws clause in printName() Name-B None of these Value-A Compilation succeed but no output Compilation fails-Exception NullPointerException is not compatible with throws clause in printName() ANSWER DOWNLOAD EXAMIANS APP
JAVA Exceptions What will be the output of the following piece of code:class Person{ public void talk() {}}public class Test{ public static void main(String args[]){ Person p = null; try{ p.talk(); } catch(NullPointerException e){ System.out.print("There is a NullPointerException. "); } catch(Exception e){ System.out.print("There is an Exception. "); } System.out.print("Everything went fine. "); }} This code will not compile, because in Java there are no pointers. There is a NullPointerException. There is a NullPointerException. Everything went fine. There is a NullPointerException. There is an Exception. This code will not compile, because in Java there are no pointers. There is a NullPointerException. There is a NullPointerException. Everything went fine. There is a NullPointerException. There is an Exception. ANSWER DOWNLOAD EXAMIANS APP
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