JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

"exception" is printed.
"null pointer exception" is printed.
Compilation fails saying NullPointerException has already been caught.
None of these
"one" is printed.

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JAVA Exceptions
What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }}

Prints out: Exception Finally
Prints out: Exception
Compile with error
None of these
Prints out: Finally

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JAVA Exceptions
Given the following piece of code:class SalaryCalculationException extends Exception{}class Person{ public void calculateSalary() throws SalaryCalculationException{ //... throw new SalaryCalculationException(); //... }}class Company{ public void paySalaries(){ new Person().calculateSalary(); }}Which of the following statements is correct?1. This code will compile without any problems.2. This code will compile if in method paySalaries() we return a boolean in stead of void.3. This code will compile if we add a try-catch block in paySalaries().4. This code will compile if we add throws SalaryCalculationException in the signature of method paySalaries().

2 and 3
1 and 4
3 and 4
2 and 4
1 and 2

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