Declaration and Access Control
What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

None of these
two
one
Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.
Compile error - char can't be permitted in switch statement.

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Which statements are most accurate regarding the following classes?class A{ private int i; protected int j;}class B extends A{ private int k; protected int m;}

An object of B contains data fields i, j, k, m.
An object of B contains data fields j, k, m.
An object of B contains data fields k, m.
An object of B contains data fields j, m.

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
A method within a class is only accessible by classes that are defined within the same package as the class of the method. Which one of the following is used to enforce such restriction?

Do not declare the method with any accessibility modifiers.
Declare the method with the keyword protected.
Declare the method with the keyword public and private.
Declare the method with the keyword public.
Declare the method with the keyword private.

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int args...){}
static void add(int...args){}
static void add(int... args, int y){}
void add(Integer... args){}
static void add(int[]... args){}

ANSWER DOWNLOAD EXAMIANS APP

Declaration and Access Control
Determine output:public class InitDemo{static int i = demo();static{ System.out.print(i); }InitDemo(){System.out.print("hello1");}public static void main(String... args){ System.out.print("Hello2");} static int demo(){ System.out.print("InsideDemo");return 10;}}

InsideDemo 10 Hello2 hello1
InsideDemo 10 Hello2
Hello2 InsideDemo 10
Compilation error.
IllegalArgumentException is thrown at runtime.

ANSWER DOWNLOAD EXAMIANS APP