Problems on H.C.F and L.C.M What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder? 123 121 116 112 123 121 116 112 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123
Problems on H.C.F and L.C.M he maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 91 1001 1911 910 91 1001 1911 910 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number of four digits which when divided by 10, 15, 21 and 28 leaves 4, 9, 15 and 22 as remainders respectively? 9654 9666 9664 9864 9654 9666 9664 9864 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two digits number is 2160 and their HCF is 12. The numbers are: (12,180) (36,60) (96,25) (72,30) (12,180) (36,60) (96,25) (72,30) ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 26, 36 and 46 leaves the remainders 12, 22 and 32 respectively. 17050 10570 10750 10075 17050 10570 10750 10075 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The maximum number of student amoung them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : 1001 91 1911 910 1001 91 1911 910 ANSWER DOWNLOAD EXAMIANS APP
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