Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12, 15, 18 and 27. 9620 9720 8760 8720 9620 9720 8760 8720 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 3 4 5 6 3 4 5 6 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number which can divide 1356, 1868 and 2764 leaving the same remainder 12 in each case, is: 124 64 156 260 124 64 156 260 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2:3. the sum of the numbers is: 32 40 64 28 32 40 64 28 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is: 80 120 200 40 80 120 200 40 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x, 4x and 5x.Then, their L.C.M. = 60x.So, 60x = 2400 or x = 40. The numbers are (3 x 40), (4 x 40) and (5 x 40).Hence, required H.C.F. = 40.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that sum is divisible by 5, 6, 4, 3? 21 23 25 27 21 23 25 27 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 5,6,4,3 is 60.On dividing 2497 by 60 we get 37 as remainder.Therefore number to be added is 60 - 37 =23.
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