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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other

66
77
55
88

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of two numbers = Product of their HCF and LCMSo Other number =(693×11/99)                              = 77

Problems on H.C.F and L.C.M
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

689
268
1015
432

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015

Problems on H.C.F and L.C.M
The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is?

1496
1494
1349
1994

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The greatest number which can divide 1356,1868 and 2764 leaving the same remainder 12 in each case, is :

124
124
260
64

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is

1032
1022
1008
1015

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find largest number of 4 digits divisible by 12, 15, 18, 27 ?

10478
11340
9720
12765

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The largest 4 digit number is 9999.We know that , if LCM of given numbers divide a number N , then N is exactly divisible by all the given numbers .LCM of 12,15,18,27 is 540.On dividing 9999 by 540 we get 279 as remainder.Therefore number =9999 - 279 =9720.

MORE MCQ ON Problems on H.C.F and L.C.M

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