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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The Smallest number which when diminished by 7, is divisible by 12,16,18,21 and 28 is :

1032
1008
1015
1022

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the least number which when divided by 16, 18, 20 and 2 leaves 4 as remainder in each case , but when divided by 7 leaves no. remainder

18002
17004
18004
18000

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

23/37
17/29
31/45
11/13

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
The G.C.D. of 1.08, 0.36 and 0.9 is:

0.03
0.18
0.108
0.9

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 Given numbers are 1.08, 0.36 and 0.90.   H.C.F. of 108, 36 and 90 is 18, H.C.F. of given numbers = 0.18.

Problems on H.C.F and L.C.M
Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively.

1394
1294
1494
1194

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6.    Required number = (L.C.M. of 20,25,35,40) – 6 =1394.

Problems on H.C.F and L.C.M
Find the largest number of four digits exactly divisible by 12,15,18 and 27.

6720
9720
7720
8720

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The Largest number of four digits is 9999.       Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.      On dividing 9999 by 540,we get 279 as remainder .   Required number = (9999-279) = 9720.

MORE MCQ ON Problems on H.C.F and L.C.M

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