Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 3 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 693 . If one of the numbers is 77, find the other . 77 99 88 95 77 99 88 95 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M L.C.M. of two prime numbers x and y (x > y) is 161 The value of 3y – x is: -1 -2 2 1 -1 -2 2 1 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 23/37 11/13 17/29 31/45 23/37 11/13 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is: 360 1260 540 180 360 1260 540 180 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work? 37 39 40 35 37 39 40 35 ANSWER DOWNLOAD EXAMIANS APP
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