Power Systems What is the correct expression for the electrical power developed by ( 75 / 0.736 ) × WQHη. ( 0.763 / 75 ) × WQHη. ( 7 / 75 ) × WQHη. 75 × 0.736 × WQHη. ( 75 / 0.736 ) × WQHη. ( 0.763 / 75 ) × WQHη. ( 7 / 75 ) × WQHη. 75 × 0.736 × WQHη. ANSWER DOWNLOAD EXAMIANS APP
Power Systems The load current in short circuit calculations are neglected because nether 1 nor 2 short circuit currents are greatly out of phase with load currents both 1 and 2 short circuit currents are much larger than load currents nether 1 nor 2 short circuit currents are greatly out of phase with load currents both 1 and 2 short circuit currents are much larger than load currents ANSWER DOWNLOAD EXAMIANS APP
Power Systems Earthing switch is used for protection of equipment from ground faults discharging residual energies measuring of safety voltage All of these protection of equipment from ground faults discharging residual energies measuring of safety voltage All of these ANSWER DOWNLOAD EXAMIANS APP
Power Systems A 3-phase breaker is rated at 2000 MVA, 33 kV, its making current will be 49 kVA. 89.22 kVA. 70 kVA. 35 kVA. 49 kVA. 89.22 kVA. 70 kVA. 35 kVA. ANSWER DOWNLOAD EXAMIANS APP
Power Systems As the frequency of the system is increased, the charging MVAR remains unaffected decreases None of these increases remains unaffected decreases None of these increases ANSWER DOWNLOAD EXAMIANS APP
Power Systems In a power system with negligible resistance, the fault current at a point is 8.00 pu. The series reactance is to be included at the fault point to limit the short circuit. current to 5.00 pu is 0.075 pu. 3.000 pu. 0.200 pu. 0.125 pu. 0.075 pu. 3.000 pu. 0.200 pu. 0.125 pu. ANSWER DOWNLOAD EXAMIANS APP
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