JAVA Exceptions
What happen in case of multiple catch blocks?

None of these
The superclass exception must be caught first.
The superclass exception cannot caught first.
Either super or subclass can be caught first.

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JAVA Exceptions
Predict the output:public class Test{ public static void main(String args[]){ try{ String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); }catch(Exception ex){ System.out.print("exception"); }catch(NullPointerException nex){ System.out.print("null pointer exception"); } }}

"null pointer exception" is printed.
"exception" is printed.
"one" is printed.
Compilation fails saying NullPointerException has already been caught.
None of these

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JAVA Exceptions
What will be the result after the class Test execution?class A{ public void doA(){ B b = new B(); b.dobB(); System.out.print("doA"); }}class B{ public void dobB(){ C c = new C(); c.doC(); System.out.print("doB"); }}class C{ public void doC(){ if(true) throw new NullPointerException(); System.out.print("doC"); }}public class Test{ public static void main(String args[]){ try{ A a = new A(); a.doA(); }catch(Exception ex){ System.out.print("error"); } }}

"doCdoBdoA" is printed
nothing is printed
"error" is printed
"doAdoBdoC" is printed
"doBdoAerror" is printed

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JAVA Exceptions
What will be the result of executing the following code?public class Test{ public void divide(int a, int b){ try{ int c = a / b; }catch(Exception e){ System.out.print("Exception "); }finally{ System.out.println("Finally"); } public static void main(String args[]){ Test t = new Test(); t.divide(0,3); }}

Prints out: Exception
Prints out: Finally
Compile with error
None of these
Prints out: Exception Finally

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