JAVA Exceptions
What happen in case of multiple catch blocks?

The superclass exception must be caught first.
The superclass exception cannot caught first.
Either super or subclass can be caught first.
None of these

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JAVA Exceptions
Given the code. What is the result when this program is executed?public class Test{ static int x[]; static{ x[0] = 1; } public static void main(String args[]){ }}

ArrayIndexOutOfBoundsException is thrown
None of these
ExceptionInInitializerError is thrown
IllegalStateException is thrown
StackOverflowException is thrown

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JAVA Exceptions
What is the output for the below code ?import java.io.FileNotFoundException;class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); }}class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); }}public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); }}

None of these
Name-B
printName()
Compilation succeed but no output
Compilation fails-Exception NullPointerException is not compatible with throws clause in
Value-A

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JAVA Exceptions
What will be the result after the class Test execution?class A{ public void doA(){ B b = new B(); b.dobB(); System.out.print("doA"); }}class B{ public void dobB(){ C c = new C(); c.doC(); System.out.print("doB"); }}class C{ public void doC(){ if(true) throw new NullPointerException(); System.out.print("doC"); }}public class Test{ public static void main(String args[]){ try{ A a = new A(); a.doA(); }catch(Exception ex){ System.out.print("error"); } }}

"error" is printed
nothing is printed
"doAdoBdoC" is printed
"doBdoAerror" is printed
"doCdoBdoA" is printed

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