Theory of Machine The rotor of a ship rotates in clockwise direction when viewed from stern and the ship takes a left turn. The effect of gyroscopic couple acting on it will be To raise the bow and lower the stern To raise the bow and stern To lower the bow and stern To raise the stern and lower the bow To raise the bow and lower the stern To raise the bow and stern To lower the bow and stern To raise the stern and lower the bow ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two pulleys of radii r₁ and r₂ and at distance x apart are connected by means of an open belt drive. The length of the belt is π (r₁ + r₂) + (r₁ - r₂)²/x + 2x π (r₁ + r₂) + (r₁ + r₂)²/x + 2x π (r₁ - r₂) + (r₁ + r₂)²/x + 2x π (r₁ - r₂) + (r₁ - r₂)²/x + 2x π (r₁ + r₂) + (r₁ - r₂)²/x + 2x π (r₁ + r₂) + (r₁ + r₂)²/x + 2x π (r₁ - r₂) + (r₁ + r₂)²/x + 2x π (r₁ - r₂) + (r₁ - r₂)²/x + 2x ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the crank is at the inner dead center, in a reciprocating steam engine, then the acceleration of the piston will be ω²r. n/(n + 1) ω²r. n/(n - 1) ω²r. (n - 1)/n ω²r. (n + 1)/n ω²r. n/(n + 1) ω²r. n/(n - 1) ω²r. (n - 1)/n ω²r. (n + 1)/n ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The equivalent length of a simple pendulum which gives the same frequency as a compound pendulum is (kG² + h²)/h h/(kG² + h²) h²/(kG² + h²) (kG² + h²)/h² (kG² + h²)/h h/(kG² + h²) h²/(kG² + h²) (kG² + h²)/h² ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Angular acceleration of a link can be determined by dividing the Resultant acceleration with length of link Tangential component of acceleration with length of link Centripetal component of acceleration with length of link All of these Resultant acceleration with length of link Tangential component of acceleration with length of link Centripetal component of acceleration with length of link All of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The behaviour of gases can be fully determined by 4 laws 1 law 3 laws 2 laws 4 laws 1 law 3 laws 2 laws ANSWER DOWNLOAD EXAMIANS APP
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