Theory of Machine The locus of a point on a thread unwound from a cylinder will be A circle A straight line Cycloidal Involute A circle A straight line Cycloidal Involute ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Flexible coupling is used because It prevents shock transmission and eliminates stress reversals It is easy to engage and disengage It is easy to disassemble It transmits shocks gradually It prevents shock transmission and eliminates stress reversals It is easy to engage and disengage It is easy to disassemble It transmits shocks gradually ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A system of masses rotating in different parallel planes is in dynamic balance if the Resultant force is numerically equal to the resultant couple, but neither of them need necessarily be zero Resultant couple is equal to zero Resultant force is equal to zero Resultant force and resultant couple are both equal to zero Resultant force is numerically equal to the resultant couple, but neither of them need necessarily be zero Resultant couple is equal to zero Resultant force is equal to zero Resultant force and resultant couple are both equal to zero ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine To obviate axial thrust, following gear drive is used Double helical gears having opposite teeth Mutter gears Single helical gear in which one of the teeth of helix angle a is more Double helical gears having identical teeth Double helical gears having opposite teeth Mutter gears Single helical gear in which one of the teeth of helix angle a is more Double helical gears having identical teeth ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine If the damping factor for a vibrating system is unity, then the system will be Under damped Without vibrations Over damped Critically damped Under damped Without vibrations Over damped Critically damped ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a reciprocating steam engine, when the crank has turned from inner dead centre through an angle θ, the angular velocity of the connecting rod is given by ω cosθ/(n² - sin²θ)1/2 ω sinθ/(n² - cos²θ)1/2 ω sinθ/(n² - sin²θ)1/2 ω cosθ/(n² - cos²θ)1/2 ω cosθ/(n² - sin²θ)1/2 ω sinθ/(n² - cos²θ)1/2 ω sinθ/(n² - sin²θ)1/2 ω cosθ/(n² - cos²θ)1/2 ANSWER DOWNLOAD EXAMIANS APP
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