Machine Design The cracks in helical springs used in railway carriages usually start on the inner side of the coil because of the fact that It is subjected to a higher stress than the outer side It is subjected to a higher cyclic loading than the outer side It has a lower curvature than the outer side It is more stretched than the outer side during the manufacturing process It is subjected to a higher stress than the outer side It is subjected to a higher cyclic loading than the outer side It has a lower curvature than the outer side It is more stretched than the outer side during the manufacturing process ANSWER DOWNLOAD EXAMIANS APP
Machine Design A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is τ. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be 4 τ τ τ/2 2 τ 4 τ τ τ/2 2 τ ANSWER DOWNLOAD EXAMIANS APP
Machine Design A shaft is subjected to fluctuating loads for which the normal torque (T) and bending moment (M) are 1000 N-m and 500 N-m respectively. If the combined shock and fatigue factor for bending is 1.5 and combined shock and fatigue factor for torsion is 2, then the equivalent twisting moment for the shaft is 2100 N-m 2136 N-m 2050 N-m 2000 N-m 2100 N-m 2136 N-m 2050 N-m 2000 N-m ANSWER DOWNLOAD EXAMIANS APP
Machine Design The product of the diametral pitch and circular pitch is equal to 1/π π × number of teeth π 1 1/π π × number of teeth π 1 ANSWER DOWNLOAD EXAMIANS APP
Machine Design Which of the following has threads at both ends? Bolt Stud Tap bolt None of these Bolt Stud Tap bolt None of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given by Where m = mass of belt per meter (kg/m) v = belt velocity (m/s) f = coefficient of friction a = angle of wrap (radians) (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα ANSWER DOWNLOAD EXAMIANS APP
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