Surveying The correction applied to the measured base of length ‘L’ is Sag = L³w²/24P² where w is the weight of tape/m All of these Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports Tension = (P - Ps)L/AE Sag = L³w²/24P² where w is the weight of tape/m All of these Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports Tension = (P - Ps)L/AE ANSWER DOWNLOAD EXAMIANS APP
Surveying According to Napier's Rules of circular parts for a right angled triangle, sine of middle part equals the product of Cosines of two adjacent parts Tangents of two adjacent parts Sines of two adjacent parts Both (A) and (B) above Cosines of two adjacent parts Tangents of two adjacent parts Sines of two adjacent parts Both (A) and (B) above ANSWER DOWNLOAD EXAMIANS APP
Surveying If ‘δ’ is the declination of the star and ‘φ’ is the latitude of the observer then the hour angle of the star at elongation is given by tan H = tan φ . cot δ None of these sin H = tan φ . cot δ cos H = tan φ . cot δ tan H = tan φ . cot δ None of these sin H = tan φ . cot δ cos H = tan φ . cot δ ANSWER DOWNLOAD EXAMIANS APP
Surveying If the staff is not held vertical at a level¬ling station, the reduced level calculated from the observation would be None of these true R.L. less than true R.L. more than true R.L. None of these true R.L. less than true R.L. more than true R.L. ANSWER DOWNLOAD EXAMIANS APP
Surveying Pick up the incorrect statement from the following. The angular distance of heavenly bodies on observer's meridian measured from the pole, is Polar distance Co-latitude Co-declination Co-altitude Polar distance Co-latitude Co-declination Co-altitude ANSWER DOWNLOAD EXAMIANS APP
Surveying If the intercept on a vertical staff is ob-served as 0.75 m from a tacheometer, the horizontal distance between tacheometer and staff station is 75 m 50 m 25 m 7.5 m 75 m 50 m 25 m 7.5 m ANSWER DOWNLOAD EXAMIANS APP
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