Surveying The correction applied to the measured base of length ‘L’ is Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports Sag = L³w²/24P² where w is the weight of tape/m All of these Tension = (P - Ps)L/AE Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports Sag = L³w²/24P² where w is the weight of tape/m All of these Tension = (P - Ps)L/AE ANSWER DOWNLOAD EXAMIANS APP
Surveying If ‘δ’ is the declination of the star and ‘φ’ is the latitude of the observer, then the azimuth of the star at elongation is given by None of these sin z = sec φ . cos δ tan z = sec φ . cos δ cos z = sec φ . cos δ None of these sin z = sec φ . cos δ tan z = sec φ . cos δ cos z = sec φ . cos δ ANSWER DOWNLOAD EXAMIANS APP
Surveying If the altitudes of a star at its upper and lower transits are 60° 30' and 19° 30' respectively, the latitude of the place, is 35° 45° 30° 60° 35° 45° 30° 60° ANSWER DOWNLOAD EXAMIANS APP
Surveying If a star whose declination is 60° N culminates at zenith, its altitude at the lower culmination, is 40° 10° 20° 30° 40° 10° 20° 30° ANSWER DOWNLOAD EXAMIANS APP
Surveying The two point problem and three point problem are methods of traversing resection and orientation orientation resection traversing resection and orientation orientation resection ANSWER DOWNLOAD EXAMIANS APP
Surveying If α, H, A and δ be the altitude, hour angle, azimuth and declination of a circumpolar star at its elongation, in latitude λ, the following relation holds good cos H = tan λ/tan δ sin A = cos δ/cos λ All listed here sin α = sin λ/sin δ cos H = tan λ/tan δ sin A = cos δ/cos λ All listed here sin α = sin λ/sin δ ANSWER DOWNLOAD EXAMIANS APP
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