Engineering Mechanics One joule is equal to 10 N-m 0.1 N-m 100 N-m 1 N-m 10 N-m 0.1 N-m 100 N-m 1 N-m ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The linear velocity of a body rotating at ω rad/s along a circular path of radius r is given by ω²/r ω.r ω².r ω/r ω²/r ω.r ω².r ω/r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics A couple produces Translatory motion Combined translatory and rotational motion Rotational motion None of these Translatory motion Combined translatory and rotational motion Rotational motion None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The center of gravity of a quadrant of a circle lies along its central radius (r) at a distance of 0.5 r 0.6 r 0.8 r 0.7 r 0.5 r 0.6 r 0.8 r 0.7 r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG - Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The principle of transmissibility of forces states that, when a force acts upon a body, its effect is Different at different points on its line of action Minimum, if it acts at the center of gravity of the body Same at every point on its line of action Maximum, if it acts at the center of gravity of the body Different at different points on its line of action Minimum, if it acts at the center of gravity of the body Same at every point on its line of action Maximum, if it acts at the center of gravity of the body ANSWER DOWNLOAD EXAMIANS APP
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