Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 6 3 4 5 6 3 4 5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 120/11 55/601 11/120 601/55 120/11 55/601 11/120 601/55 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number of that is exactly divisible by 4, 12, 15, and 18? 150 110 180 60 150 110 180 60 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of (4, 12, 15, and 18) 2|4 12 15 18 3|2 6 15 9 2|2 2 5 3 1 1 5 3 Least number which is exactly divisible by 4,12,15 and 18 is =180
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the length 7m, 3m 85cm, 12 m 95 cm is 42 cm 35 cm 15 cm 25 cm 42 cm 35 cm 15 cm 25 cm ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The H.C.F of two numbers is 8. Which of the following can never be their L.C.M? 24 48 60 56 24 48 60 56 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: 128 126 127 125 128 126 127 125 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5)= H.C.F. of 1651 and 2032 = 127.
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