Problems on H.C.F and L.C.M Find the greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively. 445 127 221 379 445 127 221 379 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 _______1651 ) 2032 ( 1 1651 1651_______ 381 ) 1651 ( 4 1524_________ 127 ) 381 ( 3 381 0Required number = 127.
Problems on H.C.F and L.C.M Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. 18004 17004 18002 18000 18004 17004 18002 18000 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: 601/55 55/601 11/120 120/11 601/55 55/601 11/120 120/11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 21 23 24 22 21 23 24 22 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 8 : 27 : 12 hrs. 5 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 8 : 27 : 12 hrs. 5 : 27 : 12 hrs. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number which when divided by 16, 18 and 21, leave the remainder 3, 5 and 8 respectively is: 995 982 1024 893 995 982 1024 893 ANSWER DOWNLOAD EXAMIANS APP
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