Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 22 23 21 24 22 23 21 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number? 103 101 113 107 103 101 113 107 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder? 123 112 116 121 123 112 116 121 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123
Problems on H.C.F and L.C.M Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case? 4 3 5 6 4 3 5 6 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2:3. the sum of the numbers is: 28 32 40 64 28 32 40 64 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is: 1449 1459 1439 1440 1449 1459 1439 1440 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS