Problems on H.C.F and L.C.M The least number,which when divided by 48,60,72,108 and 140 leaves 38,50,62,98 and 130 as remainder respectively, is : 15120 15110 15210 11115 15120 15110 15210 11115 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the greatest number which divides 29, 32, 38 and leaves same remainder in each case? 5 2 4 3 5 2 4 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find the other number ? 99 97 98 100 99 97 98 100 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers= HCF x LCM 77 x a = 11 x 693Other number a = (11×693)/77 = 99.
Problems on H.C.F and L.C.M Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are 5, 10, 15 12, 24, 36 10, 20, 30 4, 8, 12 5, 10, 15 12, 24, 36 10, 20, 30 4, 8, 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. 17004 18000 18002 18004 17004 18000 18002 18004 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 3 minute 48 seconds 1 minute 48 seconds 4 minute 48 seconds 2 minute 48 seconds 3 minute 48 seconds 1 minute 48 seconds 4 minute 48 seconds 2 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
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