Theory of Machine In a screw jack, the effort required to lift the load W is given by (where α = Helix angle, and φ = Angle of friction) P = W tan(α + φ) P = W cos(α + φ) P = W tan(α - φ) P = W tan(φ - α) P = W tan(α + φ) P = W cos(α + φ) P = W tan(α - φ) P = W tan(φ - α) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A rotor which is balanced statically but not dynamically is supported on two bearings L apart and at high speed of the rotor, reaction on the left bearing is R. The right side of the bearing is shifted to a new position 2L apart from the left bearing. At the same rotor speed, dynamic reaction on the left bearing in the new arrangement will Remain same as before Become equal to R/4 Become equal to 2R Become equal to R/2 Remain same as before Become equal to R/4 Become equal to 2R Become equal to R/2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When a point at the end of a link moves with constant angular velocity, its acceleration will have Tangential component only Radial and tangential components both Radial component only Coriolis component only Tangential component only Radial and tangential components both Radial component only Coriolis component only ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The two links OA and OB are connected by a pin joint at O. If the link OA turns with angular velocity ω₁ rad/s in the clockwise direction and the link OB turns with angular velocity ω₂ rad/s in the clockwise direction, then the rubbing velocity at the pin joint O is (where r = Radius of the pin at O) (ω₁ - ω₂)r (ω₁ - ω₂)2r (ω₁ + ω₂)r ω₁.ω₂.r (ω₁ - ω₂)r (ω₁ - ω₂)2r (ω₁ + ω₂)r ω₁.ω₂.r ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Efficiency of a screw jack is given by tan (α - φ)/tanα tanα/tan (α - φ) tanα/tan (α +φ) tan (α + φ)/tanα tan (α - φ)/tanα tanα/tan (α - φ) tanα/tan (α +φ) tan (α + φ)/tanα ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The equivalent length of a simple pendulum which gives the same frequency as a compound pendulum is (kG² + h²)/h² h²/(kG² + h²) h/(kG² + h²) (kG² + h²)/h (kG² + h²)/h² h²/(kG² + h²) h/(kG² + h²) (kG² + h²)/h ANSWER DOWNLOAD EXAMIANS APP
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