Surveying If θ and δ be the latitude of an observer and declination of a heavenly body respectively, the upper culmination of the body will be south of zenith if its zenith distance, is θ - δ θ + δ δ - θ ½ (θ - δ) θ - δ θ + δ δ - θ ½ (θ - δ) ANSWER DOWNLOAD EXAMIANS APP
Surveying The Polaris remains below horizon at 5° S latitude Equator 10° N 50° N Latitude 5° S latitude Equator 10° N 50° N Latitude ANSWER DOWNLOAD EXAMIANS APP
Surveying For adjusting a quadrilateral whose both the diagonals are observed, the equations of conditions involved, are One angle equation and three side equations Three angle equations and one side equation None of these Two angle equations and two side equations One angle equation and three side equations Three angle equations and one side equation None of these Two angle equations and two side equations ANSWER DOWNLOAD EXAMIANS APP
Surveying A star in northern sphere is said to transit When its azimuth is 180° All listed here When its altitude is maximum When it is in south When its azimuth is 180° All listed here When its altitude is maximum When it is in south ANSWER DOWNLOAD EXAMIANS APP
Surveying The station where observations are not made, but the angles at the station are used in triangulation series, is known as Pivot station Subsidiary station Main station Satellite station Pivot station Subsidiary station Main station Satellite station ANSWER DOWNLOAD EXAMIANS APP
Surveying If ‘δ’ is the declination of the star and ‘φ’ is the latitude of the observer, then the azimuth of the star at elongation is given by sin z = sec φ . cos δ tan z = sec φ . cos δ cos z = sec φ . cos δ None of these sin z = sec φ . cos δ tan z = sec φ . cos δ cos z = sec φ . cos δ None of these ANSWER DOWNLOAD EXAMIANS APP
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