Surveying If θ and δ be the latitude of an observer and declination of a heavenly body respectively, the upper culmination of the body will be south of zenith if its zenith distance, is ½ (θ - δ) θ + δ δ - θ θ - δ ½ (θ - δ) θ + δ δ - θ θ - δ ANSWER DOWNLOAD EXAMIANS APP
Surveying Pick up the correct statement from the following. The difference between the longitudes of the places is obtained. By adding their longitudes if places are in the different hemispheres All of these By subtracting the sum of their longitudes exceeding 180° from 360° if places are in different hemispheres By subtracting their longitudes if places are in the same hemisphere By adding their longitudes if places are in the different hemispheres All of these By subtracting the sum of their longitudes exceeding 180° from 360° if places are in different hemispheres By subtracting their longitudes if places are in the same hemisphere ANSWER DOWNLOAD EXAMIANS APP
Surveying The maximum tolerance in a 20 m chain is ±5 mm ±8 mm ±2 mm ±3 mm ±5 mm ±8 mm ±2 mm ±3 mm ANSWER DOWNLOAD EXAMIANS APP
Surveying 23 cm × 23 cm photographs are taken from a flying height with a camera of focal length of 3600 m and 15.23 cm respectively. A parallax difference of 0.01 mm represents 3 m 4 m 1 m 2 m 3 m 4 m 1 m 2 m ANSWER DOWNLOAD EXAMIANS APP
Surveying If α, H, A and δ be the altitude, hour angle, azimuth and declination of a circumpolar star at its elongation, in latitude λ, the following relation holds good sin α = sin λ/sin δ sin A = cos δ/cos λ All listed here cos H = tan λ/tan δ sin α = sin λ/sin δ sin A = cos δ/cos λ All listed here cos H = tan λ/tan δ ANSWER DOWNLOAD EXAMIANS APP
Surveying The negative sign is assigned to Reduction to mean sea level Correction for horizontal alignment Correction for slope All listed here Reduction to mean sea level Correction for horizontal alignment Correction for slope All listed here ANSWER DOWNLOAD EXAMIANS APP
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