Problems on H.C.F and L.C.M Find the least number which when divided by 26, 36 and 46 leaves the remainders 12, 22 and 32 respectively. 17050 10075 10570 10750 17050 10075 10570 10750 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is: 200 120 40 80 200 120 40 80 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 3x, 4x and 5x.Then, their L.C.M. = 60x.So, 60x = 2400 or x = 40. The numbers are (3 x 40), (4 x 40) and (5 x 40).Hence, required H.C.F. = 40.
Problems on H.C.F and L.C.M Find the least multiple of 23,which when divided by 18,21 and 24 leaves remainders 7,10 and 13 respectively. 3002 3036 3024 3013 3002 3036 3024 3013 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M of 22, 54, 108, 135 and 198 is 330 1980 5940 11880 330 1980 5940 11880 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the greatest number which divides 29, 32, 38 and leaves same remainder in each case? 5 4 2 3 5 4 2 3 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 17/29 23/37 11/13 31/45 17/29 23/37 11/13 31/45 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
EXAMIANS