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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the least multiple of 23,which when divided by 18,21 and 24 leaves remainders 7,10 and 13 respectively.

3024
3036
3013
3002

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Three numbers are in the ratio of 2 : 3 : 4 and their L.C.M. is 240. Their H.C.F. is:

20
30
60
40

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

11/13
17/29
31/45
23/37

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

Problems on H.C.F and L.C.M
Find the largest number of four digits exactly divisible by 12,15,18 and 27.

9720
7720
8720
6720

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The Largest number of four digits is 9999.       Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.      On dividing 9999 by 540,we get 279 as remainder .   Required number = (9999-279) = 9720.

Problems on H.C.F and L.C.M
252 can be expressed as a product of primes as:

2 x 2 x 2 x 3 x 7
2 x 3 x 3 x 3 x 7
2 x 2 x 3 x 3 x 7
3 x 3 x 3 x 3 x 7

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Clearly, 252 = 2 x 2 x 3 x 3 x 7.

Problems on H.C.F and L.C.M
Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are:

10, 20, 30
10, 20, 30
4, 8, 12
5, 10, 15

ANSWER DOWNLOAD EXAMIANS APP
MORE MCQ ON Problems on H.C.F and L.C.M

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