Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 17/29 23/37 11/13 31/45 17/29 23/37 11/13 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are: 5, 10, 15 4, 8, 12 10, 20, 30 10, 20, 30 5, 10, 15 4, 8, 12 10, 20, 30 10, 20, 30 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 20, 25, 35 and 40 leaves remainders 14, 19, 29, and 34 respectively . 1394 1384 1295 1354 1394 1384 1295 1354 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively. 1194 1294 1394 1494 1194 1294 1394 1494 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6. Required number = (L.C.M. of 20,25,35,40) – 6 =1394.
Problems on H.C.F and L.C.M In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are? 820,369 820,360 800,500 700,400 820,369 820,360 800,500 700,400 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm 265 cm 285 cm 255 cm 275 cm 265 cm 285 cm 255 cm 275 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Convert first all terms into cm.i.e. 1575 cm, 1125cm, 765cm.Now whenever we need to calculate this type of question, we need to find the HCF.HCF of above terms is 255.
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