Problems on H.C.F and L.C.M Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively. 1294 1494 1394 1194 1294 1494 1394 1194 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6. Required number = (L.C.M. of 20,25,35,40) – 6 =1394.
Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 17 16 18 19 17 16 18 19 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M The least number of five digits that have 144 their HCF is? 10070 10075 10085 10080 10070 10075 10085 10080 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which is such that when 697, 909 and 1227 are divided by it, the remainders are all the same? 53 106 108 112 53 106 108 112 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the HCF of 2.1, 1.05 and 0.63 1.21 0.21 3.21 2.21 1.21 0.21 3.21 2.21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP To solve this question quickly, first remove decimal by multiplying each term with 100,Then terms become 210, 105, 63Then HCF of above terms is 21, So Answer is 0.21
Problems on H.C.F and L.C.M The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 1001 91 910 1911 1001 91 910 1911 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS