Problems on H.C.F and L.C.M A, B and C start at the same time in the direction to run around a circular stadium. A completes a round in 252 seconds and C in 198 seconds, all starting at the same point. after what time will they 42 minutes 36 econds 45 minutes 26 minutes 18 econds 46 minutes 12 econds 42 minutes 36 econds 45 minutes 26 minutes 18 econds 46 minutes 12 econds ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 8 6 4 2 8 6 4 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M The traffic light at three different road crossing change after every 48 sec, 72 sec. and 108 sec. respectively . If they all change simultaneously at 8 : 20 : 00 hours, then at what time will they ag 5 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 8 : 27 : 12 hrs. 5 : 27 : 12 hrs. 6 : 27 : 12 hrs. 7 : 27 : 12 hrs. 8 : 27 : 12 hrs. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder. 18004 17004 18000 18002 18004 17004 18000 18002 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is: 268 432 1015 689 268 432 1015 689 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015
Problems on H.C.F and L.C.M The maximum number of student amoung them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : 910 91 1001 1911 910 91 1001 1911 ANSWER DOWNLOAD EXAMIANS APP
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