Engineering Thermodynamics Which of the following is the correct statement? All engines are designed as reversible in order to obtain maximum efficiency. All the reversible engines have the same efficiency. Irreversible engines have maximum efficiency. All the reversible and irreversible engines have the same efficiency. All engines are designed as reversible in order to obtain maximum efficiency. All the reversible engines have the same efficiency. Irreversible engines have maximum efficiency. All the reversible and irreversible engines have the same efficiency. ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Otto cycle efficiency is higher than Diesel cycle efficiency for the same compression ratio and heat input because in Otto cycle Maximum temperature is higher Combustion is at constant volume Heat rejection is lower Expansion and compression are isentropic Maximum temperature is higher Combustion is at constant volume Heat rejection is lower Expansion and compression are isentropic ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Carbonization of coal consists of Heating the wood with a limited supply of air to temperature not less than 280°C Drying and crushing the coal to a fine powder Moulding the finely ground coal under pressure with or without a binding material None of these Heating the wood with a limited supply of air to temperature not less than 280°C Drying and crushing the coal to a fine powder Moulding the finely ground coal under pressure with or without a binding material None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The term N.T.P. stands for Normal thermodynamic practice Natural temperature and pressure Nominal temperature and pressure Normal temperature and pressure Normal thermodynamic practice Natural temperature and pressure Nominal temperature and pressure Normal temperature and pressure ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The heat absorbed or rejected by the working substance is given by (where ds = Increase or decrease of entropy, T = Absolute temperature, and dQ = Heat absorbed or rejected) dQ = ds/T δQ = T/ds δQ = T.ds None of the listed here dQ = ds/T δQ = T/ds δQ = T.ds None of the listed here ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics In an isothermal process, the internal energy First increases and then decreases Increases Remain constant Decreases First increases and then decreases Increases Remain constant Decreases ANSWER DOWNLOAD EXAMIANS APP
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