Problems on H.C.F and L.C.M Two numbers are in the ratio of 15 : 11. If their H.C. F. is 13, Find he numbers . 195 and 163 185 and 133 195 and 143 175 and 123 195 and 163 185 and 133 195 and 143 175 and 123 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 6, 7, 8, 9 and 10 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 19 leaves no remainder? 5054 5073 5035 5016 5054 5073 5035 5016 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers are in the ratio of 15:11. If their H.C.F. is 13, find the numbers. 395, 343 295, 243 95, 43 195, 143 395, 343 295, 243 95, 43 195, 143 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required numbers be 15.x and 11x.Then, their H.C.F. is x. So, x = 13.The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.
Problems on H.C.F and L.C.M The ratio of numbers is 3:4 and their H.C.F is 4. Their L.C.M is: 12 24 16 48 12 24 16 48 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 6 3 5 4 6 3 5 4 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, 11 : 31 am 9 : 31 am 10 : 31 am 12 : 31 am 11 : 31 am 9 : 31 am 10 : 31 am 12 : 31 am ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 60 and 62 seconds is 1860 seconds1860/60 = 31 minutesThey will beep together at 10:31 a.m.Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
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